This code can work, but it can not reach my request, since i don't want to delete the file to check if it is open. The listdir method in Python returns a list of the all files in a specific directory, as specified by the user. I wish to process all the files one, Mar 7 '07
This is not a bad solution if you have few users for the fileit is indeed a sort of locking mechanism on a private file. To be able to read a file and perform another operation in the same program, you need to add the "+" symbol to the mode, like this: Very useful, right? If the size differs during the two intervals, you know there has been a modification made to the file. This is the basic syntax for Python's open () function: open ("name of file you want opened", "optional mode") File names and correct paths If the text file and your current file are in the same directory ("folder"), then you can just reference the file name in the open () function. This area of functionality is highly OS-dependent, and the fact that you have no control over the legacy application only makes things harder unfortunately. which is a default package in Python. If the code is not indented, it will not be considered part of the context manager. To handle these exceptions, you can use a try/except statement. The legacy application is opening and closing the file every X minutes, but I do not want to assume that at t = t_0 + n*X + eps it already closed the file. This is my current working directory: With this mode, you can create a file and then write to it dynamically using methods that you will learn in just a few moments. On Mar 7, 6:28 am, "Ros" Eloise Olivia Katherine Taylor,
Jamie Kah Ben Melham Relationship,
University Of Wisconsin Bootcamp,
Articles P
